$R = \rho \fraclA$ or $l = \fracR A\rho$ Area ($A$) = $\pi r^2 = 3.14 \times (0.25 \times 10^-3)^2$ $A = 3.14 \times 6.25 \times 10^-8 \text m^2$
Resistance is inversely proportional to the area of cross-section ($A$), and area is proportional to the square of the radius ($r^2$) or diameter ($d^2$). If diameter is doubled, Area becomes $2^2 = 4$ times larger. Since $R \propto \frac1A$, if Area becomes 4 times, Resistance becomes $\frac14$ times. New Resistance = $\frac104 = 2.5 \ \Omega$. The resistance decreases from $10 \ \Omega$ to $2.5 \ \Omega$. electricity ncert solutions class 10
Electricity is a fundamental part of our daily lives. It powers our homes, schools, and industries, and is a crucial aspect of modern technology. In Class 10, students learn about the basics of electricity, including its definition, types, and applications. $R = \rho \fraclA$ or $l = \fracR
Answer: Step 1: Calculate total current drawn by the three appliances. Voltage ($V$) = $220 \text V$ Parallel combination resistance ($R_p$): $$\frac1R_p = \frac1100 + \frac150 + \frac1500$$ $$\frac1R_p = \frac5500 + \frac10500 + \frac1500 = \frac16500$$ $$R_p = \frac50016 = 31.25 \ \Omega$$ New Resistance = $\frac104 = 2
Answer: An electric circuit is a continuous and closed path through which electric current flows. It consists of components like conductors, switches, batteries, bulbs, etc., connected in a loop. If the circuit is broken anywhere, the current stops flowing.
Voltage pushes, current flows, resistance opposes. Master that, and you’ve won half the battle.